Thevenin’s theorem
Thevenin's Theorem states that it is
possible to simplify any linear
circuit, no matter how complex, to an equivalent circuit with just a
single voltage source and series resistance connected to a load. The
qualification of “linear” is identical to that found in the
Superposition Theorem, where all the underlying equations must be
linear. If we're dealing with passive components, this is true.
However, there are some components which are nonlinear: that is, their
opposition to current changes with voltage and/or current. As such, we would call circuits containing these types of components, nonlinear circuits.
Thevenin's Theorem is especially useful in analyzing power systems and other circuits where one particular resistor in the circuit (called the “load” resistor) is subject to change, and re-calculation of the circuit is necessary with each trial value of load resistance, to determine voltage across it and current through it.
Thevenin's Theorem is especially useful in analyzing power systems and other circuits where one particular resistor in the circuit (called the “load” resistor) is subject to change, and re-calculation of the circuit is necessary with each trial value of load resistance, to determine voltage across it and current through it.
In finding the thevenin's resistance RTh, we need to consider two cases:
Case 1: If the network has no dependent sources, we turn off all independent sources. Rth is the inpit resistance of the network looking between terminals a and b, as shown below:
Case 2: if the network has dependent sources. As with Superposition, dependent sources are not to be turned off because they are controlled by circuit variables.
Sample problem: Determine the thevenin’s equivalent circuit between the terminals A&B For the circuit shown :
Answer:
First we are about to find the thevenin’s resistance. To find the thevenin’s resistance we remove the resistance RL and open circuit the AB terminals. Then we remove the voltage source and short circuit it.
We can easily find the thevenin’s resistance now.
Rth = (5//10 + 3)
Now we have to find the thevenin’’s voltage. For this we
remove the load resistance RL.
Applying nodal equation method to point c,
(V-30)/5 + (V-0)/10 = 0
V = 20V
From figure 11.3 you can see that,
VA = VC
VA = VTH
Therefore V = VTH
VTH = 20VNORTON'S THEOREM
Edward Lawry Norton was an accomplished Bell Labs engineer and scientist famous fordeveloping the concept of the Norton equivalent circuit. |
Norton resistances are equal; that is,
To find the Norton current IN, we determine the short-circuit current flowing from a to b in both circuits.
Original Circuit |
Norton Equivalent Circuit |
Since the two circuits are equivalent. Thus,
Dependent and independent sources are treated the same way as in Thevenin's theorem. Observe the close relationship between Norton's and Thevenin's theorems. Rn = Rth, and:
This is essentially source transformation. For this reason, source transformation is often called Thevenin-Norton Transformation.
Sample Problem:
Find the Norton’s equivalent circuit across A-B
terminals for the circuit shown.
Answer:
First we remove the 10Ω resistor and short circuit the
terminals A&B.
The current flowing through the short circuited terminals is
called the Norton’s curren IN.
To find the IN we apply nodal equation for point
C
(V – 30)/5 + V/10 + V/3 = 0
V = 180/19
Ohms law to 3Ω resistance
I = V/R
IN = (180/19) / 3
IN = 60/19
This is the Norton’s current.
Now we are about to find the Norton’s resistance. Note that
this is equal to the thevenin’s resistance also.
RN = (10//5) + 3
RN = 19/3Ω
TO KNOW MORE ABOUT THEVENIN'S AND NORTON'S THEOREM: